Which term of an AP 5;15;25____ will be 130 more than its 31st term?
Answers
Answered by
34
First we need to find the 31st term
The formula for finding 31st term is a + 30d
So lets find
An = a + (n-1)d
= 5 +( 31-1)*(10)
= 5 + 300 = 305
Therefore 31st term is 305!
Now 305 + 130 ( given in question) = 435
Now we need to find which term has number 435!
We need to find n
Therefore in this condition we have An = 435
So,
An = a + (n-1)d
435 = 5 + (n-1)10
435-5 = 10n-10
430+10=10n
440 = 10n
Therefore 10n =440
Therefore n =44
It means answer is 44th term!
Hope it helps!
Regards,
Mann02
Ambitous
The formula for finding 31st term is a + 30d
So lets find
An = a + (n-1)d
= 5 +( 31-1)*(10)
= 5 + 300 = 305
Therefore 31st term is 305!
Now 305 + 130 ( given in question) = 435
Now we need to find which term has number 435!
We need to find n
Therefore in this condition we have An = 435
So,
An = a + (n-1)d
435 = 5 + (n-1)10
435-5 = 10n-10
430+10=10n
440 = 10n
Therefore 10n =440
Therefore n =44
It means answer is 44th term!
Hope it helps!
Regards,
Mann02
Ambitous
Answered by
7
this is the answer
I hope it helps you
I hope it helps you
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Mann02:
Wrong answer
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