Which term of an AP 5;15;25____ will be 130 more than its 31st term?
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Here, In this question,
a= 5
d= 10
First we will find 31st term,so,
n=31
31st term = a+(n-1)d= 5+30*10=305
Now, As per the question,
nth term = 130+305 = 435
Again, By the formula of finding nth term,
435= 5+(n-1)10
435 = 5+10n -10
440= 10n
i.e. n = 44.
a= 5
d= 10
First we will find 31st term,so,
n=31
31st term = a+(n-1)d= 5+30*10=305
Now, As per the question,
nth term = 130+305 = 435
Again, By the formula of finding nth term,
435= 5+(n-1)10
435 = 5+10n -10
440= 10n
i.e. n = 44.
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