which term of an ap 5 15 25......will be 130 more than its 31th term
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a= 5
d = 10
T31 = a + 30 d
= 5 + 30*10
= 5 + 300
= 305
Tn = 305 + 130
a+(n-1)d = 435
=> 5 + (n-1)10= 435
=> (n-1) *10= 430
=> n-1 = 43
=> n = 44
Required term is 44
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d = 10
T31 = a + 30 d
= 5 + 30*10
= 5 + 300
= 305
Tn = 305 + 130
a+(n-1)d = 435
=> 5 + (n-1)10= 435
=> (n-1) *10= 430
=> n-1 = 43
=> n = 44
Required term is 44
Hope it will help you
Please mark as brainliest if you liked the solution
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