Question

which term of AP 4,9,14,19 is 79

Answer 1

$\mathbb{\huge{\purple{SOLUTION}}}$

tn = a + (n-1) d

79 = 4 + (n-1)5

79 = 4 + 5n - 5

79 = 5n - 1

5n = 79 + 1

5n = 80

n = 80/5

$\boxed{n = 16}$

${\bold{\green{\text{Hope It Helps Dear}}}}$

Answer 2

Answer:

an= a+(n-1) d

79 = 4 + (n -1) 5

79 = 4 + 5n -5

79 = 5n - 1

5n = 79 + 1

5n = 80

n = 80/5

n = 16