Question

Which term of AP 72,68,64,60,....is0

Answer 1

Step-by-step explanation:

0=72+(n-1)-4

0=72-4n+4

0=76-4n

n=19 OK friend

Answer 2

$\huge\boxed{Answer:-}$

Here,

a = 72 , d = ( a2 - a) = ( 68 - 72 ) = - 4

Let, nth term of an Ap is 0

so , an = 0

↦a + ( n - 1 ) d = 0

↦ 72 + ( n - 1 ) -4 = 0

↦ 72 - 4n + 4 = 0

↦ 76 - 4n = 0

↦ -4n = -76

↦ n = -76 / -4

↦ n = 19

. ° . 19th term Of The Ap Is 0.