Which term of G.P 0.004+0.02+0.1+••••••••••• is 12.5
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By using the formula,
Tn = arⁿ-1
Given:
a = 0.004
r = t2/t1 = (0.02/0.004)
= 5
Tn = 12.5
n = ?
So, Tn = ar^n-1
12.5 =(0.004) (5)^n-1
12.5/0.004 = 5^n-1
3000 = 5^n-1
5^5 = 5^n-1
5 = n-1
n = 5 + 1 = 6
∴ 6th term of the progression 0.004, 0.02, 0.1, …. is 12.5.
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