Question

which term of sequence ​

Answer 1

Answer:

its not an ap....

Step-by-step explanation:

I think it's hp...cause their ratios also not same

Answer 2

Answer:

Sequence is a G.P.

$a = \frac{1}{ \sqrt{2} } \\ \\ r = \sqrt{2} \\ \\ 16 = ( \frac{1}{ \sqrt{2} } ) {( \sqrt{2}) }^{n - 1} \\ \\ 16 = {( \sqrt{2}) }^{n - 2} \\ \\ {( \sqrt{2}) }^{8} = {( \sqrt{2} )}^{n - 2} \\ \\ n - 2 = 8 \\ \\ n = 10$