Question

Which term of sequence 8,12,16,20...is 48

Answer 1

Given: The series 8,12,16,20...

To find: Which term of sequence 8,12,16,20...is 48 ?

Solution:

• Now we have given the series as:

                 8 , 12 , 16 , 20........

• Here first term is 8, common difference is 4 and last term is 48.

• We have to find the n.

• So we have the formula:

                 a(n) = a + (n-1) d

• So putting the values in it, we get:

                 48 = 8 + (n-1) x 4

                 48 - 8 = 4n - 4

                 40 = 4n - 4

                 40 + 4 = 4n

                 44 = 4n

                 n = 11

Answer:

            So 48 is the 11 th term of the given series.