which term of the A.P. -1,3,7,11....is 99?
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Answered by
0
Answer:
an =a+(n-1)d
99=1+(n-1)2
99-1=(n-1)2
98/2=(n-1)
49=(n-1)
n=50
Answered by
2
Here:
First term (a1) = -1
Common Difference (d) = 4
an = a + (n-1)d
99 = 1 + (n-1)(4)
99 - 1 = (n-1)(4)
100/4 = n-1
25 = n-1
25+1 = n
26 = n
So, 26th term is 99.
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