Question

which term of the A.P. 11, 8, 5, .... is -136?

Answer 1

SOLUTION :

Given : first term (a) = 11 , common difference (d) = 8 - 11 = -3

Let -140 be the nth term

an = a + (n - 1) d

-140 = a+(n-1)d

-140 = 11+(n-1) (-3)

-140 = 11 -3n +3

-140 = 14 - 3n

3n = 140 +14

3n=154

3n= 154

n = 154/3

n = 51.333…..

But n should be an integer

Hence -140 is not the term of the given AP

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Answer 2

Answer:

50 th term

Step-by-step explanation:

Let the n th term be - 136 .

Let the first term be a .

The common difference is 8 - 11 = - 3 .

d = 8 - 11 = -3

d = 5 - 8 = - 3

a = 11

We know that the n th term is given by the formula :-

a + ( n - 1 ) d

So we are given that the n th term is - 136 .

⇒ a + ( n - 1 )d = - 136

⇒ 11 + ( n - 1 )( - 3 ) = - 136

⇒ - 3 n + 3 = - 136 - 11

⇒ - 3 n = 147 - 3

⇒ - 3 n = - 150

⇒ n = - 150/-3

⇒ n = 50

The term - 136 is the 50 th term .