Question

Which term of the A.P. 14, 9, 4, – I, – 6, ... is – 41 ?

Answer 1

✬ 12th term ✬

Step-by-step explanation:

Given:

• AP series is 14 , 9 , 4, – I, – 6, ... is – 41

To Find:

• Which term of AP is –41 ?

Solution: Let n terms of AP be –41. As we know that AP series is given by

★ aⁿ = a + (n – 1)d ★

Here in in series we have

• a = first term = 14
• d = common difference = 9 – 14 = –5
• aⁿ = – 41

Put the values in formula

$\implies{\rm }$ –41 = 14 + (n – 1)–5

$\implies{\rm }$ –41 = 14 + (–5n + 5)

$\implies{\rm }$ –41 = 14 – 5n + 5

$\implies{\rm }$ –41 = 19 – 5n

$\implies{\rm }$ –41 – 19 = – 5n

$\implies{\rm }$ –60 = – 5n

$\implies{\rm }$ 60 = 5n

$\implies{\rm }$ 60/5 = n

$\implies{\rm }$ 12 = n

Hence, 12th term of AP is –41.

Answer 2

$\huge{\mathbb{\red{ANSWER}}}$

The given AP is 14, 9, 4, -1, -6, …. Its first term = 14 and common difference = (9-14) = -5. ∴ 12th term = -41.

$\huge{\mathbb{\green{12th.term =-41}}}$