Which term of the A.P.3, 15, 27, 39, ... will be 120 more than its 21st term?
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Answer:
Step-by-step explanation:
let find 21st term
in A.P d=12
a=3
n=21
21st term
=a+(n-1)d
=3+20x12
=243
add 120 to 21st term
=243+120
363
let find which is that
363=3+(n-1)12
360=12(n-1)
30=n-1
n=31
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