Math, asked by kk9567966, 8 months ago

Which term of the A. P. 5,13, 21 ---- is 181 ?

25

24

23

32

Answers

Answered by Anonymous
49
  • 23th term of AP is 181 .

Step-by-step explanation:

To Find :

  • which term of Given AP is 181.

Given :

  • AP = 5 ,13, 21

Solution :

  • First term (a) = 5

Common difference :

  • a2 = 13
  • a1 = 5

»a2 - a1 = 13 - 5

»a2 - a1 = 8

»a3 - a2 = 21 - 13

»a3 - a2 = 8

  • »a2 - a1 = a3 - a2 = 8

So,

  • Common difference (d) = 8

As we know that,

  \underline{ \red{ \boxed{\boldsymbol{  { \purple\star }\:  a_n = a + (n - 1)d}}}}

Now,

  • an = 181
  • a = 5
  • d = 8
  • n = ?

⇒181 = 5 + (n - 1)8

⇒181 - 5 = (n - 1)

⇒176/8 = (n - 1)

⇒22 = n - 1

⇒ 22 + 1 = n

  • n = 23

Hence ,

  • \bf{\dag\:23th \:term \:of \:AP \:is\: \red{181}}

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Answered by Anonymous
26

Answer:

c) 23

Step-by-step explanation:

an = a + (n - 1)d

an = last term = 181

a = first term = 5

d = common difference = 8

n is number of terms which we have to find

Simply substitute the values,

→ 181 = 5 + (n - 1)8

→ 181 - 5 = (n - 1)8

→ 176 = (n - 1)8

Divide by 8 on both sides,

→ 176/8 = (n - 1)8/8

→ 22 = (n - 1)

→ 22 + 1 = n

→ 23 = n

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