Question

Which term of the A.P. 5,15,25....will be 130 more than its 31st term.

Answer 1

Here Is Your Ans ⤵

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Answer :-

➡44

Given :-

➡Ap is 5 , 15 , 25 .......

➡a = 5

➡d = 15 - 5 = 10

Formula :-

➡An = a + ( n - 1 )d

To Find :-

➡Which Term Of The Given AP Will Be 130 More Than Its 31st Term

Solution :-

➡31st term = a + 30d

➡31st term = 5 + 30 × 10

➡31st term = 5 + 300

➡31st term = 305

➡An = 305 + 130

➡An = 435

➡An = a + ( n - 1 )d

➡435 = a + ( n - 1 )d

➡435 = 5 + ( n - 1 )10

➡435 - 5 = ( n - 1 )10

➡430 ÷ 10 = ( n - 1 )

➡43 = n - 1

➡$\fbox{ \fbox{ \: n = 44 \: }}$

Hence , The 44th Term Of The Given AP Will Be 130 More Than Its 31st Term

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Answer 2

Answer:

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