Question

which term of the A.P 5,8,11,14.....is 320

Answer 1

let the nth term be 320
here a =5 and d=3
tn=a+(n-1)×d
320=5+(n-1)×3
320=5+3n-3
320=3n+2
3n=318
n=106

Answer 2

Answer:

Therefore, 106th term of the given A.P. is 320

Step-by-step explanation:

The A.P. is given to be 5, 8, 11, 14, .....

We need to find which term is 320

Now, First term, a = 5

Common Difference = 3

Let last term, l = 320

Now, l = a + (n - 1)d

⇒ 320 = 5 + (n - 1) × 3

⇒ 315 = (n - 1) × 3

⇒ 105 = n - 1

⇒ n = 106

Therefore, 106th term of the given A.P. is 320