Question

Which term of the A.P. 6, 13, 20, 27, ... will be 98 more than its 31st term?

Answer 1

Answer:

45th term of the given AP is 98 more it's 31st term

Answer 2

Given,

The A.P is 6,13,20,27...and so on.

To find,

The number of term of the given A.P which is 98 more than it's 31st term.

Solution,

At first,we have to calculate the 31st term of the given A.P by using the following mathematical formula.

Tn = a + (n-1)d

[Tn = nth term , a = first term of A.P, d = common difference]

By putting the value we get that,

31st term = 6+(31-1)×7 = 216

Now,the specified term = 216+98 = 314

Let,the xth term of the AP is the specified term. [Assume,x as a variable to do the further mathematical calculations.]

xth term = 6+(x-1)×7 = 6+7x-7 = 7x-1

Now, comparing the value of the specified term that we have calculated and the value that is given in the question,we get the following mathematical equation ;

7x-1 = 314

7x = 315

x = 45

Hence,45th term of the given A.P will be 98 more than it's 31st term.