Question

✌✌
Which term of the AP: 121, 117, 113, . . ., is its first negative term? ✌✌

Answer 1

Answer:

Step-by-step expllanation:

A=121

D=117-121=-4

Our nth term is 1st negative term.

An=a+(n-1)d

We now that negative term >0

0 =121+(n-1)×-4

0= 121-4n+4

0=125-4n

125=4n

n=125÷4

n=31.25

We know that in an aps term is not in decimals.

Since, we let n= 32 term

So check it by putting value .

Answer 2

Answer:

Step-by-step explanation:

a=121

d=-4

an=a + (n-1)d

ATP, an<0(negative term)

121 + (n-1)-4<0

121 -4n + 4 <0

-4n<-125

n>-125/-4

n>31.25

Since n cannot be a fraction, n=32

an=121-124

-3 is the first negative number and the term=32