Which term of the AP : 121, 117, 113... is the first negative term ?
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Step-by-step explanation:
Given A.P is 121,117,113...............
a = 121 and d = 117 − 121 = −4
a n =a+(n−1)d
=121 + (n−1) (−4)
=121 − 4n + 4
=125 − 4n
We have find the first term of this A.P.
Therefore
a n <0
125 − 4n < 0
124 < 4n
n > 4/125
n > 31.25
n = 32
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