Question

.Which term of the AP :125,120,115,....is the first negative?​

Answer 1

Answer:

$27^{th} term$

Step-by-step explanation:

Let the $n^{th}$ AP be given by:

a+(n-1)d  where a=125

                          d=-5

Now to find the term which is zero:

$a+(n-1)d=0\\\\125-5(n-1)=0\\\\n-1=25\\\\n=26$

So the term next to $26^{th}$ term will be negative,

i.e the first negative term is $27^{th}$ term

Hope this answer helped you :)