which term of the AP 3 , 10 , 17, ......... will be 84 more than its 13th term
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Answered by
6
Given AP is 3,10,17.....
First-term a = 3.
Common difference d = 10 - 3 = 7.
We know that Sum of n terms an = a + (n - 1) * d ------ (1)
a13 = 3 + (13 - 1) * 7
= 3 + 12 * 7
= 3 + 84
= 87.
Let the nth term be 84 more than its 13th term.
an = a13 + 84
= 87 + 84
= 171. -----------(2)
Substitute (2) in (1), we get
171 = 3 + (n - 1) * 7
171 - 3 = (n - 1) * 7
168 = (n - 1) * 7
168 = 7n - 7
168 + 7 = 7n
175 = 7n
n = 25.
Therefore the required term is the 25th term.
Hope this helps!
First-term a = 3.
Common difference d = 10 - 3 = 7.
We know that Sum of n terms an = a + (n - 1) * d ------ (1)
a13 = 3 + (13 - 1) * 7
= 3 + 12 * 7
= 3 + 84
= 87.
Let the nth term be 84 more than its 13th term.
an = a13 + 84
= 87 + 84
= 171. -----------(2)
Substitute (2) in (1), we get
171 = 3 + (n - 1) * 7
171 - 3 = (n - 1) * 7
168 = (n - 1) * 7
168 = 7n - 7
168 + 7 = 7n
175 = 7n
n = 25.
Therefore the required term is the 25th term.
Hope this helps!
Answered by
1
Answer:
25
Step-by-step explanation:
Given AP is 3,10,17.....
First-term a = 3.
Common difference d = 10 - 3 = 7.
We know that Sum of n terms an = a + (n - 1) * d ------ (1)
a13 = 3 + (13 - 1) * 7
= 3 + 12 * 7
= 3 + 84
= 87.
Let the nth term be 84 more than its 13th term.
an = a13 + 84
= 87 + 84
= 171. -----------(2)
Substitute (2) in (1), we get
171 = 3 + (n - 1) * 7
171 - 3 = (n - 1) * 7
168 = (n - 1) * 7
168 = 7n - 7
168 + 7 = 7n
175 = 7n
n = 25.
Hope This helps you. ....
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