which term of the AP : 3, 15, 27, 39,,... will be 132 more than its 54th term .
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Step-by-step explanation:
a = 3
d = 12
let the no of term be x
xth term = 132 + 54th term
a + (x-1)d = 132 + a + 53d
3 + (x-1)12 = 132 + 3 + 53(12)
(x-1)12 = 12(11 + 53)
so, x-1 = 64
so, x = 65
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