Question

Which term of the AP:3, 15, 27, 39, will be 132 more than its 54th term?​

Answer 1

Answer:

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Answer 2

Answer:

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Explanation:

Given: 3, 15, 27, 39, ….

First we need to calculate 54th term.

We know that,

an= a + (n – 1) d

Here, a = 3, d = 15 – 3 = 12 and n = 54

So, a54 = 3 + (54 – 1)12

⇒ a54 = 3 + 53 × 12

⇒ a54 = 3 + 636

⇒ a54 = 639

Now, the term is 132 more than a54 is 132 + 639 = 771

Now,

a + (n – 1)d = 771

⇒ 3 + (n – 1)12 = 771

⇒ 3 + 12n – 12 = 771

⇒ 12n = 771 + 12 – 3

⇒ 12n = 780

⇒ n = 65

Hence, the 65th term is 132 more than the 54th term.