Which term of the AP:3, 15, 27, 39.... will be 132 more than its 54th term?
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Answer:
65th term
Step-by-step explanation:
AP:3, 15, 27, 39....
a = 3 , d = 15 - 3 = 12 , n = 54
an = a + d(n - 1)
an = 3 + 12(54 - 1)
= 3 + (12 * 53)
= 3 + 636
an = 639
am = 639 + 132
am = 771
am = a + d(m - 1)
771 = 3 + 12(m - 1)
771 - 3 = 12(m - 1)
12(m - 1) = 768
m - 1 = 768 / 12
m - 1 = 64
m = 65
∴ 65th term is 132 more than its 54th term
Thank You
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