Question

which term of the ap 3 7 11 15 is 163

Answer 1

Step-by-step explanation:

An = a + (n-1) d

163 = 3 + 4n - 4

163 = 4n -1

164 = 4n

n = 41

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Answer 2

41 th term of the AP 3 , 7 , 11 , 15 is 163

Given :

The AP 3 , 7 , 11 , 15

To find :

Which term of the AP 3 , 7 , 11 , 15 is 163

Concept :

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

Solution :

Step 1 of 2 :

Find general term of the AP

Here the given AP is

3 , 7 , 11 , 15

First term = a = 3

Common Difference = d = 7 - 3 = 4

Hence nth term of the AP

= a + ( n - 1 )d

= 3 + ( n - 1 ) × 4

= 3 + 4n - 4

= 4n - 1

Step 2 of 2 :

Find the required term

By the given condition

4n - 1 = 163

⇒ 4n = 163 + 1

⇒ 4n = 164

⇒ n = 41

41 th term of the AP 3 , 7 , 11 , 15 is 163

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