Question

which term of the AP:8,14,20,26 will be 72 more than its 41st term

Answer 1

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Answer 2

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MysticdMaths AryaBhatta

Answer:

53 rd term of given A.P

Explanation:

Given A.P:

8,14,20,26, ...

First term (a) = 8

common difference (d) =

= 14-8

= 6

d = 6

Let n th term of A.P will be 72 more than its 41 th term.

We know that,

According to the problem given,

$\implies n = 41 +12$

$\implies n = 53$

Therefore,

n = 53

53rd term in given A.P will be

72 more than its 41th term.

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