Math, asked by rupesh1388, 1 year ago

which term of the AP 92,88, 84, 80,.....is 0

Answers

Answered by Rookie7
6
an=a+(n-1)d
0=92+(n-1)-4
-92=(n-1)-4
-92/-4=n-1
n=23+1
n=24

Anonymous: pls solve my answer fast....
Answered by mysticd
10
Solution :

Given A.P : 92 , 88, 84 , 80 ,.....,0

first term ( a ) = 92

common difference ( d ) = a2 - a1

= 88 - 92

= -4

nth term = 0 ( given )

a + ( n - 1 )d = 0

=> 92 + ( n - 1 )(-4) = 0

=> (n-1)(-4) = -92

=> n - 1 = ( -92 )/( -4 )

=> n - 1 = 23

=> n = 23 + 1

=> n = 24

Therefore ,

24th term in given A.P is 0 .

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