which term of the AP 92,88, 84, 80,.....is 0
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an=a+(n-1)d
0=92+(n-1)-4
-92=(n-1)-4
-92/-4=n-1
n=23+1
n=24
0=92+(n-1)-4
-92=(n-1)-4
-92/-4=n-1
n=23+1
n=24
Anonymous:
pls solve my answer fast....
Answered by
10
Solution :
Given A.P : 92 , 88, 84 , 80 ,.....,0
first term ( a ) = 92
common difference ( d ) = a2 - a1
= 88 - 92
= -4
nth term = 0 ( given )
a + ( n - 1 )d = 0
=> 92 + ( n - 1 )(-4) = 0
=> (n-1)(-4) = -92
=> n - 1 = ( -92 )/( -4 )
=> n - 1 = 23
=> n = 23 + 1
=> n = 24
Therefore ,
24th term in given A.P is 0 .
••••
Given A.P : 92 , 88, 84 , 80 ,.....,0
first term ( a ) = 92
common difference ( d ) = a2 - a1
= 88 - 92
= -4
nth term = 0 ( given )
a + ( n - 1 )d = 0
=> 92 + ( n - 1 )(-4) = 0
=> (n-1)(-4) = -92
=> n - 1 = ( -92 )/( -4 )
=> n - 1 = 23
=> n = 23 + 1
=> n = 24
Therefore ,
24th term in given A.P is 0 .
••••
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