which term of the AP121,117 , 133 , ...... is its first negative term
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a = 121
d = 117-121 = -4
an = a +(n-1)d<0
an = 121 + (n-1)-4<0
an = 121-4n +4<0
125< 4n
n = 125/4
n = 31.25
so, it is approx 32
so, 1st negative term is 32th term
here is your answer
d = 117-121 = -4
an = a +(n-1)d<0
an = 121 + (n-1)-4<0
an = 121-4n +4<0
125< 4n
n = 125/4
n = 31.25
so, it is approx 32
so, 1st negative term is 32th term
here is your answer
Answered by
12
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