Question

Which term of the day sequence 1 3 7 11 is 95?

Answer 1

1,3,7,11
a=1 d=3-1=2 an=95
An=a+(n-1)d
95=1+(n-1)(2)
95-1=1+(n-1)(2)
94=(n-1)(2)
94/2=(n-1)
47=(n-1)
48=n

Answer 2

$\infty \: hey \: mate \: \infty$
Here is your answer..,,




SOLUTION :-
=> 1 , 3 , 7 , 11 ...... and so on.

$a = 1$
$d = 2$
$tn = 95$

now,,


$tn = a + (n - 1)d$
$95 = 1 + (n - d)2$
$95 = 1 + 2n - 2$
$95 = 1 - 2n$
$95 - 1 = 2n$
$94 = 2n$
$\frac{94}{2} = n$
$47 = n$



i . e , n = 47


•hence,,

47th term of the day sequence is 95.








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