Question

which term of the following A.P is 560. 2,11,20,29,,,,,,,

Answer 1

Step-by-step explanation:

the answer to the question is the 63rd term of the AP will be 560

the explanation to this question is as follows the value of d is 11 - 2 which is 9 and the value of a is 2 and the value of a n is 560 the value of n we have to find

therefore an=a+(n-1)d

560=2+(n-1)9

558 upon 9= n-1

62=n-1

n=62+1

n=63

Ans:- 63rd term of the AP will be 560....

Answer 2

Given:

An A.P. 2,11,20,29,...

To find:

The term of the A.P. whose value is 560.

Solution:

As we know that in an A.P. having a = first term, d = common difference, the nth term is given by${n}^{th \:} \: term = a + (n - 1)d$

n = number of terms till nth term.

Now,

in the given A.P. 2,11,20,29,...

a = 2,

d = 11 - 2 = 9

nth term = 560

So,

on putting all the values in the above formula, we get

$560 = 2 + (n - 1)9$

$558 = (n - 1)9$

$n - 1 = \frac{558}{9}$

$n - 1 = 62$

$n \: = 63$

Hence, the term of the A.P. which is 560 is 63rd.