Question

Which term of the sequence 6, 9 ,12 ,15 is 126

Answer 1

Answer:

(3*2)=6

(3*3)=9

(3*4)=12

(3*5)=15

term of sequence

126/3 = 42

and (n-1)= (42-1)

and (n-1)= (42-1) = 41 no of term