Question

which terms of AP 2,11,20,29 ...560​

Answer 1

Answer:

$a_{n}$ = a+(n-1) d

560 = 2 + (n-1)9

567 = 9n

n= 567/9 = 63

63 rd term

Step-by-step explanation:

Answer 2

Answer:

63

Step-by-step explanation:

Given A.P. 2, 11, 20, 29, . .

Here a= 2, d = 11 - 2 = 9

nth term of this AP is 560

tn=a+(n-1)d

560=2+(n-1)×9

=2+9n-9

9n=567

n=567/9 = 63

Therefore, 63rd term of given AP is 560.

Thank you