Which terms of Ap 3,15,27,39 will be 132 more than 54 term?
Answer:
3, 15, 27, 39
a=3
d=15 -3=12
an = a+(n-1)d
an=132+a54
a+(n-1)d =132+(a+53d)
a+(n-1) 12=135+3+53(12)
3+(n-1)12=771
-9+12=771
12n=771+9!
12n=780
n=780/12
n=65
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