Which transition between Bohr orbit correspond to the third line in Balmer series of the hydrogen spectrum?
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We know that the Balmer series is having its first orbit n1 as 2 and since from the question we get that the third line is given so the second orbit will be having its n2 = 2 + 3 = 5.
So, from the above explanation we get that the third line of the Balmer series of the hydrogen spectrum will be corresponding to n1 =2 to n2 = 5.
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