Question

which trem of series 1,√3,3......is81​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\ Question}}$

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Which term is 81 in series..

1 , √3 , 3....

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$\huge\underline{\underline{\ Answer}}$

If you observe them they are in G. P

Whose first term is = a = 1

second term is = t2 = √3

also common ratio is = r = √3

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$\huge formula..$

$tn = a \: {r}^{(n - 1)}$

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$tn = a \: {r}^{(n - 1)} \\ 81 = 1 \times { \sqrt{3} }^{(n - 1)} \\ 81 = \frac{ { \sqrt{3} }^{n} }{ \sqrt{3} } \\ 81 \sqrt{3} = { \sqrt{3} }^{n} \\ { \sqrt{3} }^{(9)} = { \sqrt{3} }^{(n)} \\ n = 9$

So, 9th term is 81

n = 9 is correct..✅