Which trigonometry identities are most important for board exams?
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Answer:
try memorizing all of the identities
Answered by
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Understand the way how the identities are derived and you would not have to learn them
Example
Sin^2 @+cos^2 @= 1
(This is the first basic/primary Pythagorean identity)
We know that,
Sin @ =opposite/hypotenuse
Cos @=adjacent/hypotenuse
In a right angled triangle
With reference to angle @
(Let it be any two angle except 90 degrees)
According to Pythagoras theorem
(Opposite side)^2 +(adjacent side )^2 =(hypotenuse)^2
Now,
Sin^2 @ +Cos^2 @
=(opposite /hypotenuse )^2 +(adjacent/hypotenuse)^2
=[(opposite)^2+(adjacent)^2]/(hypotenuse)^2
{since,according to Pythagoras theorem
(Opposite)^2 +(adjacent)^2 =(hypotenuse)^2}
=(hypotenuse)^2/(hypotenuse)^2
=1
Hence proved
Sorry for the inconvenience I have neither have special keyboard nor I know some tricks
If you understood what I taught then I would be very happy
Thankyou
Example
Sin^2 @+cos^2 @= 1
(This is the first basic/primary Pythagorean identity)
We know that,
Sin @ =opposite/hypotenuse
Cos @=adjacent/hypotenuse
In a right angled triangle
With reference to angle @
(Let it be any two angle except 90 degrees)
According to Pythagoras theorem
(Opposite side)^2 +(adjacent side )^2 =(hypotenuse)^2
Now,
Sin^2 @ +Cos^2 @
=(opposite /hypotenuse )^2 +(adjacent/hypotenuse)^2
=[(opposite)^2+(adjacent)^2]/(hypotenuse)^2
{since,according to Pythagoras theorem
(Opposite)^2 +(adjacent)^2 =(hypotenuse)^2}
=(hypotenuse)^2/(hypotenuse)^2
=1
Hence proved
Sorry for the inconvenience I have neither have special keyboard nor I know some tricks
If you understood what I taught then I would be very happy
Thankyou
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