Question

which vertex of the triangle ABC is right angled if AB=12cm, AC=8cm, BC=10cm​

Answer 1

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In the given △ABC, AB = 12 cm, BC = 8 cm and AC = 10 cm. Find AF, BD and CE.

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Solution

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In the given figure, let CE=CF=x

It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,

AF=AD=10−x

BE=BD=8−x

Now consider,

AB=AD+BD

⇒12=10−x+8−x

⇒12=18−2x

⇒2x=18−12

⇒2x=6

⇒x=

2

6

=3

Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm

Hence, CE=3 cm, AF=7 cm and BD=5 cm.

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Answer 2

$\huge\red{A}\pink{N}\orange{S} \green{W}\blue{E}\gray{R} =$

In the given figure, let CE = CF = x

It is also given that AB = 12 cm, BC = 8 cm and AC = 10 cm, therefore,

AF = AD = 10-x

BE BD 8-X =

Now consider,

AB = AD + BD

→ 12 = 10-x+8-X

12 18-2x

2x = 18-12

→2x = 6

$x = \frac{6}{2} = 3$

Therefore, CE = x = 3 cm, AF = 10-3 = 7 cm and BD = 8-3 = 5 cm

Hence, CE = 3 cm, AF = 7 cm and BD =5 cm.