which would require a greater force,accelerating a 10 g mass at 5m/s2 or a 20 g mass at 2m/s2?
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We know that force = mass * acceeration
Therefore in first case,
Mass = 10 gram = 10/1000 kg = 0.01 kg Acceleration = 5m/s2
Therefore force = mass * acceleration = 0.01 * 5 = 0.05 Newton (N) or 0.05 kg/m2
In second case
Mass = 20 gram = 20/1000 = 0.02 kg Acceleration = 2m/s2
Therefore force = mass * acceleration = 0.02 * 2 = 0.04 Newton (N) or 0.04 kg/m2
We find that a body of 20 gram accelerating 2m/s2 requires greater force as compared to body of 10 gram accelerating 5m/s2 because force of 20 gram body is 0.04 kg/m2 which is less than force of 10 gram body (0.05 kg/m2)
Therefore in first case,
Mass = 10 gram = 10/1000 kg = 0.01 kg Acceleration = 5m/s2
Therefore force = mass * acceleration = 0.01 * 5 = 0.05 Newton (N) or 0.05 kg/m2
In second case
Mass = 20 gram = 20/1000 = 0.02 kg Acceleration = 2m/s2
Therefore force = mass * acceleration = 0.02 * 2 = 0.04 Newton (N) or 0.04 kg/m2
We find that a body of 20 gram accelerating 2m/s2 requires greater force as compared to body of 10 gram accelerating 5m/s2 because force of 20 gram body is 0.04 kg/m2 which is less than force of 10 gram body (0.05 kg/m2)
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Answer:
Explanation:
Solution :-
Given :-
Mass of the body A, m₁ = 10 g
= 10 × 10⁻³ kg
Mass of the body B, m₂ = 20 g
= 20 × 10⁻³ kg
Acceleration of body A, a₁ = 5 m/s²
Acceleration of body B, a₂ = 2 m/s²
To Calculate :-
Forces F(A) and F(B) and comparing them
Formula to be used :-
F = ma
Force of body A, F(A) = m₁a₁ = 10 × 10⁻³ × 5
F(A) = 5/100 = 0.05 N
Force of body B, F(B) = m₂a₂ = 20 × 10⁻³ × 2
F(B) = 4/100 = 0.04 N
Since F(A) > F(B), therefore, we need force to accelerate A of mass 10 g.
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