Question

While adding 2 consecutive numbers and the square of the first number, we get 9216.Which are the numbers?​

Answer 1

Answer:

95,96

Step-by-step explanation:

let the two consecutive numbers be x,x+1

required equation is

x+x+1+x^2 = 9216

$x^{2} +2x -9215 = 0$

solving by quadratic formula

here a=1, b = 2 , c = -9215

$x = \frac{-b +-\sqrt{b^{2}-4ac } }{2a}$

$x = \frac{-2 +-\sqrt{ 4-4(1)(-9215)}}{2}$

$x = \frac{-2 +- (192)}{2} \\x = 190/2\\x = 95$