Question

While boarding an aeroplane a passenger got hurt.The pilot showing promptness and concern, made arrangements to hospitalise the injured and so the plane started late by 30 minutes to reach the destination, 1500 km away in time, the pilot increased the speed by 100 km/hr. Find the original speed /hour of the plane. What values are depicted here?

Answer 1

Let the Original speed of the aeroplane be x km/h.

Time taken to cover 1500 km with the usual speed of x km/h = 1500 / x hrs
Time taken to cover 1500 km with the increase speed of (x+100) km/h = 1500 / (x+100) hrs

ATQ
1500 / x = 1500 / (x+100) + ½
1500 / x -  1500 / (x+100) = ½
1500(x+100) -1500x / x(x+100)= ½
1500x + 1500 × 100 -1500x / x² +100x = ½
1500 × 100 / x² +100x = ½
2(1500 × 100 ) = x² + 100x
300000 = x² +100x
x² +100x - 300000 =0
x² -  500 x  + 600 x - 300000= 0
x(x - 500) + 600(x - 500)= 0
(x+600)  (x - 500) = 0
(x+600)  = 0  or  (x - 500) = 0

x = -600  or  x = 500
Speed cannot be negative, so x = 500

Hence,  the usual speed of the plane is 500 km/h.

The value depicted by the pilot here are humanity.

HOPE THIS WILL HELP YOU...

Answer 2

After that middle term spilling to be done by you