Math, asked by bharatihotkar9545, 10 months ago


While landing at an airport
Average speed of the plane was
pilot made an angle of depression of 20°
of the plane was 200Km/hour. The plane reached the
n atter 54 seconds. Find the height at which the plane was when
started landing. (Sin20º = 0.342)

Answers

Answered by hardik44364
2

Step-by-step explanation:

Average speed of plane =200Km/hour

In triangle ABC

LB=90

AB is the height of plane

AC is distance of plane from ground

Speed=Dist./time

200=dist./54/60/60

Converting sec into hr

200(0.015)=dist.

3=dist.

AC=3

sintheeta =AB/AC

SIN20=AB/3

0.342(3)=AB

AB=1.026Km

AB=1026m

Height of the plane when it started landing is 1.026Km or 1026m

Similar questions