while landing at an airpot, a pilot made an angle of depression of 20°. average speed of plane was 200 km/hr. the plane reached the ground after 54 second find the height at which the plane was when it started landing . (sin 20°=0.232)
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Sin20° =perpendicular/hypothesis
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madhuraparab9:
200 x 100 upon what is written
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Answer:
Hey Mate,
Correction in Question : #Sin 20° = 0.342 not 0.242
#Figure is attach with the answer.
Speed of plane = 200 km/ hr
=> ( 200 × 5/18 )
=> ( 500/9 ) m/s
Distance = 500/9 × 54
=> 500×6
=> 3000 m = 3 K.M
AC = 3 K.M.
∠B = 20°
Height ( BC ) = X
Sin 20° = Opposite/ Hypotenuse
Sin 20° = BC/ AC ( #Sin 20° = 0.342 )
0.342 = BC/ 3
BC = 3 × 0.342
BC = 1.026 K.M
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