Question

While making a mask,Riya removed two circles of radius 7 cm each and a rectangle of length 4 cm and breadth 1 cm from a circular card of radius 42 cm as shown in the adjoining figure.Find the area of the remaining card.​

Answer 1

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Given:

In a mask, Riya removed two circles of radius 7cm each and a rectangle of length 4cm and breadth 1cm from a circular card of radius 42cm as shown in the adjoining figure.

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The area of the remaining card.

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We have,

• Two smaller circles of radius,[r]= 7cm
• Larger circular of radius,[R]= 42cm
• A rectangle of length,[l]= 4cm
• A rectangle of breadth,[b]= 1cm

A/q

• Area of larger circle:

We know that area of circle: πr²    [sq.units]

Radius of larger circle = 42cm

→ πR²

→ $\frac{22}{7} *42cm*42cm$

→ $\frac{22}{\cancel{7}} *\cancel{42}cm*42cm$

→ (22×6×42)cm²

→ 5544cm²

• Area of smaller circle:

→ πr²

→ $\frac{22}{7} *7cm*7cm$

→ $\frac{22}{\cancel{7}} *\cancel{7}cm*7cm$

→ (22×7)cm²

→ 154cm²

&

• Area of rectangle:

We know that area of rectangle: (length × Breadth)    [sq.units]

→ 4cm × 1cm

→ 4cm²

Now,

Remaining area= Ar. of larger circle - 2(Ar. of smaller circle)- area of rectangle

⇒ Remaining area= 5544cm² - 2(154cm²) - 4cm²

⇒ Remaining area= 5544cm² - 308cm² -4cm²

⇒ Remaining area= 5544cm² - 312cm²

⇒ Remaining area= 5232cm²

Thus,

The area of the remaining card is 5232cm².

Answer 2

Explanation:

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