Question

While verifying Archimedes principle, a student took a solid body and noted the following observation
A) weight of the solid in air =68gwt.
B) Weight of the empty glass beaker=57gwt
C) weight of solid in water=46gwt
D) weight of beaker+weight of displaced water=79gwt
Show that these observations verify the Archimedes principle.

Answer 1

Weight of beaker + weight of displaced water=79gwt

ATQ,weight of beaker is 57gwt

If you subtract the value of displaced water is 22gwt....

Then find the loss of weight of solid

Subtract weight in air-weight in water,it ll give you 22gwt...

According to Archimedes Principle, loss of weight of solid =weight of water displaced by the solid...

22=22

Hence it verifies Archimedes Principle.

Mark it as brainliest..

Tq

Answer 2

Weight of beaker + weight of displaced water=79gwt

ATQ,weight of beaker is 57gwt

If you subtract the value of displaced water is 22gwt....

Then find the loss of weight of solid

Subtract weight in air-weight in water,it ll give you 22gwt...

According to Archimedes Principle, loss of weight of solid =weight of water displaced by the solid...

22=22

Hence it verifies Archimedes Principle