Question

While writing a mathematical equation, a student accidentally interchanged two numbers and wrote it as
7−8÷4+5×3=8×3+6÷2−3
If the equation is mathematically correct, then the two numbers are

Answer 1

Given:

While writing a mathematical equation, a student accidentally interchanged two numbers and wrote it as

7−8÷4+5×3 = 8×3+6÷2−3

To find:

If the equation is mathematically correct, then the two numbers are

Solution:

From given, we have,

7 − 8 ÷ 4 + 5 × 3 = 8 × 3 + 6 ÷ 2 − 3

For any kind of mathematical problems, we must use BODMAS rule.

8 × 3 + 6 ÷ 2 − 3

= 24 + 3 - 3

= 24

⇒ 5 − 8 ÷ 4 + 7 × 3 = 8 × 3 + 6 ÷ 2 − 3

5 − 8 ÷ 4 + 7 × 3

= 5 - 2 + 21

= 3 + 21

= 24

LHS = RHS

24 = 24

upon interchanging the numbers 5 and 7 the given equation is mathematically correct

∴ The 2 numbers are 5 and 7

Answer 2

Given :

Equation:  7−8÷4+5×3=8×3+6÷2−3

Answer:

The answer is 8 and 3

Explanation:

This is  because 8 occurs 2 times as well as 3 occurs 3 time. If we interchange their places of the digits, the equation will be mathematically correct.  It will not affect the equation which is mathematically correct.

Hope it will help you...