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A person is holding a bucket by Applying a force of 10N. he Moves a horizontal distance of 5m and then Climbs up a vertical distance of 10m. find the total work Done by him.
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Force = 10 N
Horizontal work = force * displacement
10*5= 50 J
Vertical work = 10*10
=100 J
Total work = 100 + 50
= 150 J
Hope it helps.
Regards,
Sparkles!
luckysin:
your answer is wrong
Then you tell me the answer that is correct.
If you have that much confidence in you, ANSWER the question.
Pointing out others' mistake is very easy, but doing the same thing is definitely tough.
just wait 2 minutes
What is the answer that you calculated?
Case 1:
force= 10 N
Displacement= 5 m
Work done= FScos(theta)
=10* 5* cos(90)
= 50*0
=0J
Case 2:
Force=10 N
Displacement=10m
Work done=FScos(theta)
= 10*10*cos(180)
=100*-1
=-100
Now, total work done= 0+(-100)
=-100J
So, the total work done by the person = -100 J
force= 10 N
Displacement= 5 m
Work done= FScos(theta)
=10* 5* cos(90)
= 50*0
=0J
Case 2:
Force=10 N
Displacement=10m
Work done=FScos(theta)
= 10*10*cos(180)
=100*-1
=-100
Now, total work done= 0+(-100)
=-100J
So, the total work done by the person = -100 J
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