who can solve 10 questions of time and calendar in 10 minutes
Answers
Odd Days Concept
Suppose we have to calculate the number of odd days in 1200 years. In 1200 there are 3 years which are divided by 100 and 400. (400, 800, and 1200). And the remaining years are only divided by 100. (100, 200, 300, 500, 600, 700, 900, 1000, and 1100). Every 100 years have 76 ordinary years and 24 leap years.
Odd days in ordinary year = (52 weeks + 1) days. Odd days in a leap year = (52 weeks +2) days. So odd days in 100 years will be (76 x 1 + 24 x 2) which is 124 odd days. This can also be written as 17 weeks + 5 days. So every 100 years will have 5 odd days. Similarly, 200 years will have (5 x 2) = 3 odd days and 300 years will have 1 day.
The number of odd days in 400 years will be ( 5 x 4 + 1) because 400 is itself a leap year and that is why it has one odd day extra. Thus odd days in 400 will be 0. This is same for every year which is a multiple of 100 and 400. Thus 1200 will also have odd days. Now we will solve some examples to have a better understanding of this, concept.
Solved Examples
Q. January 2, 2007, was Tuesday. What will be the day on January 2, 2008?
1. Monday 2. Tuesday
3. Wednesday 4. Thursday
Here you can see that 2007 is neither a multiple of 4. Thus 2007 is an ordinary year. So the odd day in 2007 will be 1. Now since the 2nd day of January 2007 was Tuesday, 2nd day of January 2008 will be one day beyond Tuesday. And that is why January 2, 2008, will be Wednesday. Thus the correct answer is the option (3).
Q. For what year will the calendar be the same as for the year 2009?
1. 2021 2. 2022
3. 2023 4. 2024
For the year to have the same calendar as 2009 you need the sum of the number of odd days. When this sum is divisible by 7 than that year will have the same calendar as 2009.
Answer:
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