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Retardation = 2 m/s²
Distance traveled = 25 m
Step-by-step explanation :
Given,
u = 36 km/h
= ( 36 *5/18 ) m/s = 10m/s
v = 0
t = 5sec
( i ) retardation of the car
We know,
v = u + at
Substituting the values,
0 = 10 + a*5
0 = 10 + 5a
5a = -10
a = -10 / 5
a= -2 m/s²
Acceleration = -2 m/s²
Since acceleration is negative,
retardation = 2 m/s²
( ii ) distance travelled before it is stopped after applying the brakes
We know,
S = ut + 1/2 at²
Substituting the values,
S = 10*5 + 1/2 * (-2) * (5)²
S = 50 + 1/2* (-2) * 25
S = 50 + 1/2* (-50)
S = 50+ (-25)
S = 25m
So, Distance traveled = 25 m
Hence,
Retardation = 2 m/s²
Distance traveled = 25 m
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