Question

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Answer 1

Answer:

49m

Step-by-step explanation:

Let the base of tree be B and the point at which it s broken be A and the top of tree touching ground be C and 5he actual top be C'

Hence, a right angled triangle ABC is formed where angle B is 90 degrees.

According to given information, AB=12m ,BC=35m

Hence using Pythagoras theorem we get AC=37m

We must find BC'=AB+AC'=AB+AC=12+37=49 m

Hence the original height of tree is 49 m.

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Answer 2

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=35 m and BC=12 m

Using Pythagoras theorem, In ΔABC

(AC)^2 + (AB)^2 + (BC)^2

(AC)^2 + (35)^2 + (12)^2

(AC) ^2 = 1225 + 144

(AC) ^2= 1369

AC = 37 m

Hence, the total height of the tree = AC + CB

= 37 + 12

= 49 m.

Step-by-step explanation:

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