Math, asked by aadita20045apr, 1 year ago

who have the guts to answer this question

Attachments:

Answers

Answered by saurabhsemalti
0
here
a =   \sqrt{3}  + 1 \\ ar = 1 \\ r =  \frac{1}{ \sqrt{3} + 1 }  \\ seventh \: term \:  = a {r}^{6}  \\ seventh \: term=  \frac{1}{( \sqrt{3}  + 1) {}^{6} }
mark as brainliest if helped
Similar questions