who is intelligent in maths try to solve the above sum
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cosA/cosB = m ---( 1 )
cosA/sinB = n ------( 2 )
LHS = (m²+n²)cos²B
= [(cosA/cosB)²+(cosA/sinB)²]cos²B
= [1/cos²B+1/sin²B](cos²Acos²B)
=[(sin²B+cos²B)/(cos²Bsin²B)](cos²Acos²B)
= [(cos²Acos²B)/(cos²Bsin²B)]
= [cos²A/sin²B]
= (cosA/sinB)²
= n²
= RHS
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